b^2-b-40=2

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Solution for b^2-b-40=2 equation:


Simplifying
b2 + -1b + -40 = 2

Reorder the terms:
-40 + -1b + b2 = 2

Solving
-40 + -1b + b2 = 2

Solving for variable 'b'.

Reorder the terms:
-40 + -2 + -1b + b2 = 2 + -2

Combine like terms: -40 + -2 = -42
-42 + -1b + b2 = 2 + -2

Combine like terms: 2 + -2 = 0
-42 + -1b + b2 = 0

Factor a trinomial.
(-6 + -1b)(7 + -1b) = 0

Subproblem 1

Set the factor '(-6 + -1b)' equal to zero and attempt to solve: Simplifying -6 + -1b = 0 Solving -6 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1b = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1b = 0 + 6 -1b = 0 + 6 Combine like terms: 0 + 6 = 6 -1b = 6 Divide each side by '-1'. b = -6 Simplifying b = -6

Subproblem 2

Set the factor '(7 + -1b)' equal to zero and attempt to solve: Simplifying 7 + -1b = 0 Solving 7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b = 0 + -7 -1b = 0 + -7 Combine like terms: 0 + -7 = -7 -1b = -7 Divide each side by '-1'. b = 7 Simplifying b = 7

Solution

b = {-6, 7}

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